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Suppose we have a list of numbers called candies and two persons are racing to collect the most number of candies. Here the race is turn based, person 1 is starting first, and in each turn he can pick up candies from the front or from the back. We have to check whether person 1 can collect more candies than other or not.

So, if the input is like candies = [1, 4, 3, 8], then the output will be True, as person 1 can take 8 candies in the first round and regardless of whether second person picks 1 or 3, person 1 can win by taking any remaining candy.

To solve this, we will follow these steps −

N := size of candies

Define a function difference() . This will take left, right

if left is same as right, then

return candies[left]

return maximum of (candies[left] − difference(left + 1, right)) and (candies[right] − difference(left, right − 1))

from the main method do the following −

return true when difference(0, N − 1) > 0, otherwise false

Let us see the following implementation to get better understanding −

class Solution: def solve(self, candies): N = len(candies) def difference(left, right): nonlocal candies if left == right: return candies[left] return max(candies[left] − difference(left + 1, right), candies[right] − difference(left, right − 1)) return difference(0, N − 1) > 0 ob = Solution() candies = [1, 4, 3, 8] print(ob.solve(candies))

[1, 4, 3, 8]

True

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